IPL 2020, MI vs SRH, Mumbai Indians vs SunRisers Hyderabad: Head to Head Match Stats
IPL 2020, MI vs SRH: Mumbai Indians and SRH have beaten each other seven times.© BCCI
Defending champions Mumbai Indians will take on Sunrisers Hyderabad (SRH) in the Match 17 of the Indian Premier League (IPL) 2020 at Sharjah Cricket Stadium. Rohit Sharma and David Warner – two of the biggest entertainers in world cricket – will look to lead for example by adding two more points, with their sides and IPL points consolidating their positions in the top-half of the table. Having made their campaign debut with two straight defeats, SRH have found their combination right and have reflected in the result, beating the Delhi Capital and Chennai Super Kings. Rohit Sharma’s side has been hot and cold so far this season, losing and winning two matches each.
Although Mumbai Indians have been forced to make records in cash-rich leagues for many years, Sunrisers Hyderabad is somehow devising plans to harass them again and again and it reflects head to head statistics. While Mumbai enjoys a healthy win percentage against most sides, they have won and lost in equal proportion against the Hyderabad-based outfit.
These two sides have faced each other 14 times so far, of which the record IPL champions have won and lost seven times, one of which came in the super over.
Mumbai Indians (MI) vs Sunrisers Hyderabad (SRH)
Head to head match status
MI won: 7
SRH Won: 7
Both Mumbai and SRH are two of the most consistent batsmen in IPL history. But so far, only Rohit has been able to give his team the start they expected, while Warner has failed to give him a solid start on a consistent basis.
In addition to their captaincy, both teams would like to fire their slippers with the bat, especially given the nature of the pitch and the small dimensions of the field in Sharjah which has proved to be a run-scoring celebration so far in the tournament.